Server Variables (Measurements)

[Strakowski]

I was just looking at "Server Variables" on the wiki, and I noticed that the listing for the speed and jump velocities (tankSpeed and jumpVelocity) don't say what the units of measurement are, for either one . I'm doing some work with trampolines and quadratic parabolas, and I really need to know what these values signify.

I'm assuming that it's measured in worldUnits/second
but before I go ahead and make my projections, could someone verify this information?

Thanks!- Strakowski

[dango]

Both are indeed in worldUnits/second

[Strakowski]

Okay, thanks!

[optic delusion]

the best place to find this type of info is http://shellshock.bzflag.bz/guides-bzscience.html

[Strakowski]

Oh, wow. That's awesome. This will be fantastic when planning maps. So glad you posted that.

[Strakowski]

Wait a sec... my formula is incorrect. My calculations are telling me that the default jumpVelocity would have to be a measurement of the [height at the peak of the jump].

I know that it takes 4 seconds to jump and the default jump travels 100 units. With a gravity of [9.8 units/second^2] and default speed of 25 units/second, the jump velocity can't be 19.

My equation looks like this:

j(x/25)-9.8((x/25)^2)=y

If x is 100 and y is 0, j has to be 39.2.
I know I probably made an error, could someone disprove me? (or approve, but that seems unlikely; been a while since Algebra)

[Spazzy McGee]

I reckon I can disprove you. Hope you can read it, I proved all the information on the shellshock site: that the height of the jump is about 19 (actually, it's closer to 18), that the length of a jump is about 100 (it's actually about 95), and that the time for the jump is 4 seconds (actually 3.8). The bit you're after is the height, which is on the right hand side.

I apologise for the poor photos. I don't have a scanner.



Most of the time, it's best to consider the horizontal and vertical components separately. I calculated the height of the jump separately from the distance travelled horizontally. All you need to remember to make things really easy, are your equations of motion:
v = u + at
v^2 = u^2 + 2as
s = ut + 0.5 at^2
They can solve any projectile problem, provided that air resistance is negligible.

[joevano]

I apologise for the poor photos. I don't have a scanner.

Reminds me of pictures of Einstein's notes... did you rip him off?

[Strakowski]

Oh great! I knew something was a little strange. These values are all working great! Next post I make should be on the Map Releases page!

Thanks a million!- Strakowski

P.S. I found my fault in the equation; I forgot to cut the gravitational constant in half. I wrote "-9.8X^2", it should have been "-4.9x^2".

[Spazzy McGee]

forgot to cut the gravitational constant in half

Acceleration due to gravity is not constant

[Strakowski]

(I think I'll go bang my head against the wall now)